x(x+4)+x(x+2)=2x^2+12

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Solution for x(x+4)+x(x+2)=2x^2+12 equation: 


Simplifying
x(x + 4) + x(x + 2) = 2x2 + 12

Reorder the terms:
x(4 + x) + x(x + 2) = 2x2 + 12
(4 * x + x * x) + x(x + 2) = 2x2 + 12
(4x + x2) + x(x + 2) = 2x2 + 12

Reorder the terms:
4x + x2 + x(2 + x) = 2x2 + 12
4x + x2 + (2 * x + x * x) = 2x2 + 12
4x + x2 + (2x + x2) = 2x2 + 12

Reorder the terms:
4x + 2x + x2 + x2 = 2x2 + 12

Combine like terms: 4x + 2x = 6x
6x + x2 + x2 = 2x2 + 12

Combine like terms: x2 + x2 = 2x2
6x + 2x2 = 2x2 + 12

Reorder the terms:
6x + 2x2 = 12 + 2x2

Add '-2x2' to each side of the equation.
6x + 2x2 + -2x2 = 12 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
6x + 0 = 12 + 2x2 + -2x2
6x = 12 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
6x = 12 + 0
6x = 12

Solving
6x = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '6'.
x = 2

Simplifying
x = 2

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